Question

What is the pressure of 0.5 mol nitrogen (N2) gas in a 5.0 L container at 203 K?

Answer 1

The pressure of 0.5 mole of nitrogen gas=
`168.78 k pa`

Given:

Moles of nitrogen gas=0.5mole

Volume of nitrogen gas=5L

Temperature of nitrogen gas=203K

To Find:

Pressure of 0.5g mole of nitrogen gas

Step by Step by Explanation:

Formula used for calculating the pressure of a gas is achieved through ideal gas equation

According to Ideal Gas;

`P V=n R T`

From this above equation, pressure can be calculated as

`P=(n R T)/(V)`

Where P=Pressure of the gas

N=number of moles=0.5moles

R=Gas constant
`=8.3144598 L k p_(a) k^(-1) m o l^(-1)`

V=Volume of nitrogen gas in litres=5L

T=Temperature of nitrogen gas=203K

Substitute all the values in the above equation we get

`P=(0.5 * 8.3144598 * 203)/(5)`

`P=(843.9177)/(5)`

`P=168.78 k pa`

Result:

Thus the pressure of 0.5 mole of nitrogen gas is
`168.78 k pa`