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Consider a poisson distribution with an average of 3 customers per minute at the local grocery store. determine the expected number of customer arrivals for a five-minute period. 15 3 243 125

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The mean of the Poisson distribution remains the same at all periods, which means that it cannot have a higher mean at one place over the others.
So the mean over 5 minutes is 5*3=15 arrivals.
User Millerbr
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Answer:

15 customers.

Explanation:

Given,

There is an average of 3 customers per minute at the store,

That is,

1 minutes = 3 customers,

We need to find the number of customers for 5 minutes,

Multiply both sides by 5,

5 minutes = 5 Ă— 3 = 15 customers,

Thus, the expected number of customers for the period of 5 minutes is 15.

User Barat Sahdzijeu
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