Register
The population of fish in a certain lake increases, on average, by 1.8% per year. If there are 950 fish currently in the lake. How many fish will be in the lake after 10 years? * Your answer SUBMIT
20.6k views
5 votes
The population of fish in a certain lake increases, on average, by 1.8% per year. If there are 950 fish currently in the lake. How many fish will be in the lake after 10 years? *

Your answer

SUBMIT

User Michael Dorfman
by
5.4k points

2 Answers

3 votes

Answer:

1135 fish

Explanation:

User Sinio
by
5.3k points
4 votes
To do this, you must do 950x1.8%, and get the number. Then add that number and 950 to get the amount of fish in it after one year. Repeat those steps 9 more times and you get your answer. In this case, the answer would be 1,313 fish. Your welcome!
User Arabella
by
6.1k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.5m questions

8.6m answers

Other Questions

What is the least common denominator of the four fractions 20 7/10 20 3/4 18 9/10 20 18/25
What is 0.12 expressed as a fraction in simplest form
Solve using square root or factoring method plz help!!!!.....must click on pic to see the whole problem
What is the initial value and what does it represent? $4, the cost per item $4, the cost of the catalog $6, the cost per item $6, the cost of the catalog?
What is distributive property ?
Link Copied!