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Mason’s bedroom is 10 feet wide by 14 feet long. If the ceiling is 8 feet high, what is the total area of the four walls of Mason’s bedroom?

2 Answers

3 votes
First wall = 10 x 8 = 80
Opposite side of the first wall = same = 10 x 8 = 80
Second wall = 14 x 8 = 112
Opposite side of the second wall = same = 14 x 8 = 112
Total = 80 + 80 + 112 + 112 = 384 square feet
User Raygan
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3 votes
The area of the walls can be written as:

A_w = h(2l+2w)

We can plug in given values:

A_w = 8(2(14)+2(10)) = 8(48) = 384

So, your answer is 384 ft².
User Bukki
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5.4k points