The correct question is
Find the accumulated amount after 66 months compounded if $3000 is deposited at an interest rate of 1.6% t=66 months------------ >66/12=5.5 years
F = P*(1 +(r/m))^n
r=1.6%---------- >0.016
m=12 (number of compounding periods per year)
n=m*t---------- >12*5.5=66
we have
P=3000
t=5.5 years
F = 3000*(1 +(0.016/12))^66------------------ >3275.77 dollars
the answer is 3275.77 dollars