Question

A squirrel runs along an overhead telephone wire that stretches from the top of one pole to the next. the creature is initially at position xi = 2.31 m, as measured from the center of the wire segment. it then undergoes a displacement of δx = -5.85 m. what is the squirrel\'s final position xf?

Answer 1

The squirrel's final position on the wire segment is -3.54 m, which is 3.54 m to the left of the center of the wire segment after a displacement of -5.85 m from its initial position of 2.31 m.

Step-by-step explanation:

The student asked how to find the squirrel's final position after it moved along a telephone wire. The squirrel's initial position, xi, is 2.31 m from the center of the wire segment. After a displacement of δx = -5.85 m, to find the final position, xf, we apply the formula for displacement: δx = xf - xi. Rearranging the formula to solve for xf, we have xf = δx + xi. Plugging in the values, we get xf = -5.85 m + 2.31 m = -3.54 m. This means the squirrel's final position is 3.54 m to the left of the wire segment's center.

Answer 2

This is a one-dimensional motion on the x-axis (the wire). The initial position is
`x_i = 2.31 m`, and the displacement is
`\delta x = -5.85m`. Therefore, the final position will be

`x_f = x_i+\delta x=2.31 m - 5.85 m = -3.54m`