Question

Find three consecutive square numbers whose sum is 149(I need the steps)​

Answer 1

6,7,8

Explanation:

according to the question

x²+(x+1)²+(x+2)²=149

3x²+6x+5=149

3x²+6x+5-149=0

3x²+6x-144=0

x²+2x-48=0

(x+8)(x-6)=0

x=-8

x=6

therefore

x=6 (note: it says the consecutive numbers so -8 isn't applicable)

so the numbers are

6,(6+1),(6+2)

6,7,8