Question

Solve 9^2x=66 round to the nearest ten-thousandth

Answer 1

If you simplify it, you get x= In(66)/4in(3)
So the answer would be 0.953397... or 1 when you round it
Hope it helps

Answer 2

ANSWER


`x = 0.95340`

Step-by-step explanation

The given expression is


`{9}^(2x) = 66`

We take logarithm of both sides to base e to get,


`ln( {9}^(2x) ) = ln(66)`

This implies that,


`2x ln(9) = ln(66)`

Or


`2x ln( {3}^(2) )=ln(66)`

This implies that,


`4x ln(3) = ln(66)`

We divide both sides by 4ln(3) to get,


`x = (ln(66) )/(4 ln(3) )`

`x = 0.953397`

To the nearest ten-thousandth, we have,


`x = 0.95340`