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What is the concentration of iron ions (in M) in a 7.08 M solution of Fe3(PO4)2
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What is the concentration of iron ions (in M) in a 7.08 M solution of Fe3(PO4)2

User Rathish Cholarajan
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21.2 M
Fe3(PO4)2 when dissolved breaks up into 5 ions. 3 Fe ions, and 2 PO4 ions. So for every mole of Fe3(PO4)2 in the solution, there are 3 moles of Fe ions created. Therefore 3 * 7.08 M = 21.24M which to 3 significant figures is 21.2 M
User Nizarazu
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