1 Answer

Frankie Ribery · Answer 1 · 2019-04-16T19:48:39+0000

let's take a peek at the graph, and say get two points off the line hmmm the one on the left and the one there on the right, so (-4,5) and (8,8)

$\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ -4 &,& 5~) % (c,d) &&(~ 8 &,& 8~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{8-5}{8-(-4)}\implies \cfrac{8-5}{8+4}\implies \cfrac{3}{12}\implies \cfrac{1}{4}$

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions