Answer:
380 °C
Step-by-step explanation:
The following data were obtained from the question:
Initial volume (V₁) = 27 L
Initial temperature (T₁) = 26 °C
Final volume (V₂) = 59 L
Final temperature (T₂) =?
Next, we shall convert 26 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 26 °C
Initial temperature (T₁) = 26 °C + 273
Initial temperature (T₁) = 299 K
Next, we shall determine the final temperature of the gas. This can be obtained as follow:
Initial volume (V₁) = 27 L
Initial temperature (T₁) = 299 K
Final volume (V₂) = 59 L
Final temperature (T₂) =?
V₁ / T₁ = V₂ /T₂
27 / 299 = 59 / T₂
Cross multiply
27 × T₂ = 299 × 59
27 × T₂ = 17641
Divide both side by 27
T₂ = 17641 / 27
T₂ = 653 K
Finally, we shall convert 653 K to celsius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
T₂ = 653 K
T₂ = 653 – 273
T₂ = 380 °C
Thus, the final temperature of the gas is 380 °C