Question

What is the solution of this system of linear equations? 3y = 3/2x + 6 1/2y –1/4 x = 3

A;(3, 6)
B;(2, 1)
C;no solution
D;infinite number of solutions
hurry up plz I'm on a time and need a good grade

Answer 1

c is your answer your welcome

Answer 2

The answer is: [C]: "no solution" .
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Given: 3y = 3/2 x + 6 ; Multiply each side by "2" ; to get rid of the fraction

2 * { 3y = 3/2 x + 6 } ; to get: 6y = 3x + 12


Given: 1/2 y –1/4 x = 3 ; Multiply EACH SIDE by "4" ; to get rid of the fraction ;


4 * { 1/2 y – 1/4 x = 3 } ; to get: 2y – x = 12 ;
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So we have:

6y = 3x + 12 ;

2y – x = 12 ;
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Multiply BOTH side of the "second equation" by "-1" ;

-1 * { 2y – x = 12 } ;

to get : x – 2y = -12 ;

Now, add "2y" to each side of the equation;
to isolate "x" on one side of the equation; & to solve for "x" ;

x – 2y + 2y = -12 + 2y ;

to get: x = 2y – 12 ;

Now, consider the "first equation" ;

6y = 3x + 12 ;

Divide EACH SIDE of this equation by "3" ;

6y / 3 = (3x + 12) / 3 ;

to get: 2y = x + 4 ;

Divide EACH SIDE of the equation by "2" ;

2y/ 2 = ( x + 4) /2 ;

to get: y = (x + 4) / 2 ;

Now plug in our calculated value for "x" ; which is:

" x = 2y – 12 " ; for the "x" values


y = [ (2y – 12)] + 4)] / 2 ;

y = (2y – 8 )/ 2

2y = 2y – 8 ??? ;;

The answer is: [C]: "no solution" .
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