Question

(09.04 mc) a circle has its center at (−1, 2) and a radius of 3 units. what is the equation of the circle? (x − 1)2 + (y + 2)2 = 3 (x + 1)2 + (y − 2)2 = 3 (x + 1)2 + (y + 2)2 = 9 (x + 1)2 + (y − 2)2 = 9

Answer 1

The answer is the last one (x+12+(y-2)2=9

Explanation:

Answer 2

General formula to make an equation of circle
(x - a)² + (y - b)² = r²


Given:
the center (a,b) = (-1,2)
the radius r = 3

Solution:
plug the numbers to the formula
(x - a)² + (y - b)² = r²
(x - (-1))² + (y - 2)² = 3²
(x + 1)² + (y - 2)² = 9
The answer is the last option