Question

Find the equation of the line that contains the point (-1,-6) and is parallel to the line 5x+3y=8. Write the equation in slope-intercept form.

Answer 1

y = -(5/3)x -(23/3)

Explanation:

Rewrite the given equation is standard slope-intercept format: y = mx + b

5x + 3y = 8

3y = -5x + 8

y = -(5/3)x + (8/3)

A parallel line will have the same slope: -(5/3)

y = -(5/3)x + b

We need to find a b that will force the line through point (-1,-6).

y = -(5/3)x + b

-6 = -(5/3)*(-1) + b

-6 - (5/3) = b

b = -(23/3)

y = -(5/3)x -(23/3)