Question

F(x) = x2 + 1 g(x) = 5 – x

(f + g)(x) =

A). x2 + x – 4

B). x2 + x + 4

C). x2 – x + 6

D). x2 + x + 6

Answer 1

Option C is correct

`x^2-x+6`

Explanation:

Given the functions:

`f(x)=x^2+1`

`g(x) = 5-x`

We have to find (f + g)(x).

(f + g)(x) = f(x)+g(x)

Substitute the values we have;

`(f+g)(x) = x^2+1+5-x`

⇒
`(f+g)(x) = x^2-x+6`

Therefore, the value of (f + g)(x) is,
`x^2-x+6`

Answer 2

Option (c) is correct.

`(f + g)(x)=x^2-x+6`

Explanation:

Given :
`f(x)=x^2+1\\\\g(x)=5-x`

We have to find (f + g)(x)

Using property of addition of functions

(f + g)(x) = f(x) + g(x)

Substitute , we get,

`(f + g)(x)= f(x)+g(x)\\\\(f + g)(x)= x^2+1+5-x\\\\`

On Simplifying further , we get,

`(f + g)(x)=x^2-x+6`

Thus, option (c) is correct.

`(f + g)(x)=x^2-x+6`