Question

A. y = (x+3)^2-5

B. x = -3(y+5)^2


C. y = (x-5)^2+3


D. y = (x+3)^2+5

Answer 1

The vertex form of the parabola:

`f(x)+a(x-h)^2+k\\\\(h;\ k)-a\ vertex`

We have the coordinates of a vertex

`(-3;-5)\to h=-3;\ k=-5`

substitute:

`y=(x-(-3))^2+(-5)=(x+3)^2-5`

Answer: A. y = (x + 3)² - 5