w= walnuts
c= chocolate chips
Set up an equation for each set of #s above:
3w+2c= $14
8w+4c= $33
You have to solve for one variable in equation one, then substitute it in equation two.
3w+2c= 14
Subtract 2c from both sides
3w= 14-2c
Divide both sides by 3
w= (14-2c)/3
Substitute it in equation two.
8w+4c=33
8(14-2c)/3+4c=33
(112-16c)/3+4c=33
Multiply everything by 3 to eliminate the fraction
(3/1)((112-16c)/3)+(3)(4c) = (33)(3)
112-16c+12c=99
112-4c=99
Subtract 112 from both sides
-4c= -13
Divide both sides by -4
c=13/4= $3.25 cost for lb of chocolate chips
Substitute that answer in to the equation:
8w+4c=33
8w+4(3.25)= 33
8w+13=33
Subtract 13 from both sides
8w= 20
Divide both sides by 8
w=20/8= $2.50 cost for lb of walnuts
Check:
3w+2c=14
3(2.50)+2(3.25)=14
7.50+6.50= 14
14=14
Hope this helps!! I'll look at your other problems when I get home.