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Write an equation in the form y = mx + b for the line that has a slope of ¼ and contains the point (12, 3).

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\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ 12 &,& 3~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{1}{4} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=\cfrac{1}{4}(x-12) \\\\\\ y-3=\cfrac{1}{4}x-3 \implies y=\cfrac{1}{4}x
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