Question

"What volume of 0.642 M [Molar ]magnesium Chloride (MgCl2, MM 95.21 g/mol) solution would be required to deliver 4.50g of MgCl2?"

Answer 1

Step-by-step explanation:

n=m/MM

MM of MgCl2=95.2

n=4.5/95.211

M=n/V

0.652=0.0473/V

V=0.0724 L

=72 ml