Question

An object experiences an acceleration of 7.7 m/s^2. As a result, it accelerates from rest to 20 m/s. How much distance did it travel during that acceleration?​

Answer 1

Answer:

Answer:

pay back : the answer is 2 because 2 + 4 = 2

Step-by-step explanation:

2 + 4 = 2 your welcome

Step-by-step explanation:

Step-by-step explanation:

Answer 2

26m

Step-by-step explanation:

Given parameters:

Acceleration = 7.7m/s²

Initial velocity = 0m/s

Final velocity = 20m/s

Unknown:

Distance traveled = ?

Solution:

To solve this problem, we use the expression below:

v² = u² + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

20² = 0² + (2 x 7.7 x S)

400 = 15.4S

S = 26m