Solution:
As we know that the equation of a straight line passing through a given point and having slope m is given by
![(y-y_1)=m(x-x_1)](https://img.qammunity.org/2019/formulas/mathematics/college/wckkvq9ntmhfq3ki1whqczggyxononn2jc.png)
Here we can find the slope of the line from the given points (-3,3) and (-1,-3)
Slope of the line can be found using the formula
![m=(y_2-y_1)/(x_2-x_1)\\](https://img.qammunity.org/2019/formulas/mathematics/middle-school/cwc4luh7yzt6jd2asu70po0bv9p8h63opc.png)
Here the points are (-3,3) and (-1,-3) So the slope will be
![image](https://img.qammunity.org/2019/formulas/mathematics/middle-school/dwsy1xxicvneiqce8v8ltmgy7h2uqyxn2w.png)
Hence the equation of the straight line will be
![(y-3)=-3(x+3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lldzojunaxcr8qliij8h6hha0gafat7w11.png)
or
![(y+3)=-3(x+1)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/qfpstesv22b4szl1lxvlf9atvd12e0kdpp.png)