1 Answer

Migli · Answer 1 · 2022-01-13T02:35:35+0000

Answer:

f(g(t)) = 2t² + 1

Explanation:

You can solve this simply by substituting g(t) into f(t), and solving for f(g(t)):

$f(t) = 2t + 5\\\\g(t) = t^2 - 2\\\\f(g(t)) = 2(g(t)) + 5\\\\f(g(t)) = 2(t^2 - 2) + 5\\\\f(g(t)) = 2t^2 - 4 + 5\\\\f(g(t)) = 2t^2 + 1$

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