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A car traveling 13m/s to the north collideswith a car traveling 19m/s to the south. Each car has a mass of 1250 kg. If the system is defined as the two cars, what is the change in momentum?

User Naasia
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2 Answers

3 votes
Let P1=13m/s(1250kg)=16250 kg m/s (positive velocity is north here)
P2=-19m/s(1250kg)=-23750 kg m/s
Total system momentum is P1 + P2 = 16250 - 23750 = -7500 (negative momentum is south pointing).
Due to the conservation of momentum, this is also the final momentum and we see the two cars have a mass of 1250 + 1250 = 2500kg and have a velocity
-7500 = 2500kg * Vfinal
Final = -3m/s (moving southward)
Each car's momentum changes from the initial value it had to this final value, but the total system momentum does not change, due to the conservation law.
User ThePravinDeshmukh
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5 votes

Answer:

0

Step-by-step explanation:

Other guy worded it weird but he’s right

User Kilhoffer
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