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According to the fundamental theorem of algebra, how many zeros does the function f(x) = 15x17 + 41x12 + 13x3 − 10 have?
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According to the fundamental theorem of algebra, how many zeros does the function f(x) = 15x17 + 41x12 + 13x3 − 10 have?

User Pratik Khadka
by
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2 Answers

2 votes

Answer:

17 zeros!

Explanation:

User Josh Bush
by
8.4k points
5 votes
The number of zeroes = the number of degrees of the equation ( highest exponent.

So the answer to this one is 17 zeroes.
User Elias Prado
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