Answer:
Hence, the exponential function that best fits the data is:
(Option A)
Explanation:
We are given a set of values as:
x f(x)
3 10
4 16
5 28
so we will put the value of x=3 in each of the given options and check which function gives the value 10.
i.e. at x=3 which function f(x)=10.
B)

when x=3.

Hence, option B is incorrect.
C)

when x=3

Hence, option C is incorrect.
D)

when x=3

Hence, option D is incorrect.
A)

when x=3.

similarly A option holds for other values of x as well.
Hence, option A is correct.
Hence, the exponential function that best fits the data is:
