Question

a car can go from 0 - 45m/s in 3.4 seconds A. how much is its acceleration in m/s B. how much longer would it take the car to get up to 70m/s

Answer 1

13.2m/s²

1.89s

Step-by-step explanation:

Given parameters:

Initial velocity = 0m/s

Final velocity 1 = 45m/s

Final velocity 2 = 70m/s

Unknown:

Time taken = 3.4s

Solution:

Acceleration is the rate of change of velocity with time.

Acceleration =
`(Final velocity 1 - initial velocity )/(3.4)`

Acceleration =
`(45 - 0)/(3.4)` = 13.2m/s²

B. How much longer would it take the car to get up to 70m/s

Maintaining the is acceleration;

13.2 =
`(70 - 45)/(t)`

25 = 13.2t

t = 1.89s