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Find the angle between the diagonal of a cube of side length 18 and the diagonal of one of its faces, so that the two diagonals have a common vertex. the angle should be measured in radians. (hint: we may assume that the cube is in the first octant, the origin is one of its vertices, and both diagonals start at the origin.)

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Length of the diagonal of one of its faces = sqrt ( 2* 18^2) = 25.46

Required angle = arctan 18 / 25.46 = 0.6154 radians
User DJ Forth
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