Question

The decomposition of potassium chlorate, kclo3, is used as a source of oxygen in the laboratory. how many moles of potassium chlorate are needed to produce 15 moles of oxygen gas? worksheet

Answer 1

To produce 15 moles of oxygen gas from the decomposition of potassium chlorate, 10 moles of potassium chlorate are required according to the molar stoichiometry of the balanced chemical reaction.

Step-by-step explanation:

The decomposition of potassium chlorate (KClO3) produces potassium chloride (KCl) and oxygen gas (O2) based on the balanced chemical equation:

2 KClO3 (s) → 2 KCl (s) + 3 O2 (g)

From the equation, 2 moles of KClO3 produce 3 moles of O2. To find out how many moles of KClO3 are needed to produce 15 moles of O2, we set up a proportion:

(2 moles KClO3 / 3 moles O2) = (x moles KClO3 / 15 moles O2)

Solving this for x gives us:

x = (2 moles KClO3 / 3 moles O2) * 15 moles O2

x = 10 moles KClO3

Therefore, 10 moles of potassium chlorate are needed to produce 15 moles of oxygen gas. This calculation is based on molar stoichiometry and the balanced chemical equation provided.

Answer 2

2KClO3 ===> 2KCl + 3O2

Set up a Proportion
2 mols KClO3 . . . . . . . . . . . x
========= . . . . . . . . . . . ==============
3 moles of Oxygen . . . . . . 15 moles of oxygen

2/3 = x / 15 Cross Multiply.
2 * 15 = 3x
30 = 3x
x = 30 / 3
x = 10

So to get 15 moles of oxygen, you need 10 moles of KClO3