Question

Please answer quickly!

Answer 1

`f(x) = 3 {x}^(2) - x + 5`

thus ;

`f( - 3) = 3 * ({ - 3})^(2) - ( - 3) + 5`

`f( - 3) = 3 * 9 + 3 + 5`

`f( - 3) = 27 + 8`

`f( - 3) = 35`

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`f(4) = 3 * ({4})^(2) - (4) + 5`

`f(4) = 3 * 16 - 4 + 5`

`f(4) = 48 + 1`

`f(4) = 49`

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So :

`2f( - 3) = 2 * 35 = 70`

And ,

`- f(4) = - 49`

so :

`2f( - 3) - f(4) =`

`70 - 49 =`

`21`