Question

What is the speed of a proton whose kinetic energy is 3.4 kev ?

Answer 1

The speed of a proton with a kinetic energy of 3.4 keV is approximately 2.5 x 10^5 m/s.

Step-by-step explanation:

The speed of a proton can be determined using the formula:

speed = sqrt(2 * kinetic energy / mass)

Given that the kinetic energy of the proton is 3.4 keV and the mass of the proton is approximately 1.67 x 10-27 kg, we can calculate its speed as follows:

speed = sqrt(2 * 3.4 * 103 eV * 1.6 x 10-19 J/eV / (1.67 x 10-27 kg))

After evaluating this expression, we find that the speed of the proton is approximately 2.5 x 105 m/s.

Answer 2

the kinetic energy of the proton is 3.4 kev
1 kev = 1.602 × 10^-16 joules
therefore 3.4 kev is equivalent to;
3.4 × (1.602 ×10^-16)= 5.4468 × 10^-16 J
Kinetic energy is calculated by the formula 1/2mv² where m is the mass and v is the velocity.
Therefore V = √((2 × ( 5.4468×10^-16))/ (1.67 ×10^-27))
= 8.077 × 10^5 m/s