Answer:
A. 2.2 ɥC
Step-by-step explanation:
Given;
electric field strength, E = 1236 N/C
distance of the source charge, r = 4 m
Electric field strength is calculated as;

where;
Q is the magnitude of the source charge
k is Coulomb's constant = 9 x 10⁹ Nm²/C²

Therefore, the correct option is A. 2.2 ɥC