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A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge?

A. 2.2 ɥC
B. 680 ɥC
C. 2.2 C
D. 680 C

can someone explain this in detail because im having a hard time understanding these type questions...thank you!!

1 Answer

8 votes

Answer:

A. 2.2 ɥC

Step-by-step explanation:

Given;

electric field strength, E = 1236 N/C

distance of the source charge, r = 4 m

Electric field strength is calculated as;


E = (kQ)/(r^2)

where;

Q is the magnitude of the source charge

k is Coulomb's constant = 9 x 10⁹ Nm²/C²


E = (kQ)/(r^2) \\\\kQ = Er^2\\\\Q = (Er^2)/(k) \\\\Q = ((1236)(4^2))/(9 \ * \ 10^9) \\\\Q = 2.197 \ * \ 10^(-6) \ C\\\\Q = 2.197 \ \mu \ C

Therefore, the correct option is A. 2.2 ɥC

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