Question

Please please please help

Answer 1

See explanation.

Step-by-step explanation:

Hello!

In this case, since the main molecular reaction that is taken place in the beaker is:

`AgNO_3(aq)+BaI_2(aq)\rightarrow AgI(s)+Ba(NO_3)_2(aq)`

In such a way, we understand that one breaker contained silver nitrate and the other one barium iodide. Thus, the complete molecular equations turns out:

`2AgNO_3(aq)+BaI_2(aq)\rightarrow 2AgI(s)+Ba(NO_3)_2(aq)`

Now, for the complete ionic equation, we just ionize the aqueous species:

`2Ag^++2NO_3^-+Ba^(2+)+2I^-\rightarrow 2AgI(s)+Ba^(2+)+2(NO_3)^-`

Finally, for the net ionic equation we cancel out barium and nitrate ions as the spectator one because they are both sides on the equation:

`2Ag^++2I^-\rightarrow 2AgI(s)`

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