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How much heat does 225 g of water gain when its temperature rises from 25°C to 32°C? A. 30.12 kJ B. 21.65 kJ C. 6.59 kJ D. 0.376 kJ

User Dsgriffin
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2 Answers

4 votes
q = mc delta t

q = (225g)(4.18 J/g x C)(32C-25C)
q = 6583.5 J
q = 6.59 kJ

Answer is C
User Michael Klein
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8.8k points
5 votes
Answer:
C. 6.59 KJ

Step-by-step explanation:
To solve this question, we will use the following rule:
q = mCΔT
where:
q us the amount of heat gained that we want to calculate
m is the mass of the water = 225 grams
C is the specific heat capacity of the water = 4.184 J / g - C
ΔT is the change in temperature = Tfinal - Tinitial = 32 - 25 = 7 degrees

Substitute with the givens in the above equation to get the amount of heat gained as follows:
q = mCΔT
q = 225 * 4.184 * 7 = 6589.8 Joules = 6.5898 KJ which is approximately choice C.

Hope this helps :)
User HeyAlex
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8.2k points