Question

A helicopter hovers 200 meters over the ground and releases a relief packet. How much time does it take for the food packet to reach the ground?

Answer 1

200 m x 1s^2/9.81 m = 20.4 s

Answer 2

If it is hovering, you are being told that vi = 0 [The initial downward velocity is 0]

Givens
=====
vi = 0
a =9.81 m/s
d = 200 m

Find
====
t

Formula
=======
d = vi * t + 1/2a*t^2

Substitution and Work
================
200 = 0 + (1/2)* 9.81 * t^2
200 * 2 = a*t^2
400 = 9.81 * t^2
200 / 9.81 = t^2
20.39 = t^2
t = sqrt (20.39)
t = 4.52 seconds.