1 Answer

Ian Steffy · Answer 1 · 2019-03-25T09:10:09+0000

Consider, pls, this option:
a) not the same around x=2, in others are the same;
b) for x+2 D(f)=any; for g(x) D(g)≠2;
c) for values in (-oo;2)∪(2;+oo);
d) for value x=2. Note, that no permissions to perform operation 0/0.

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