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What is the number of moles in 526 L O2 at STP?

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526 L O2 x 1 mol O2 / 22.4 L = 23.5 mol O2
User Sachinruk
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Answer: The correct answer is : 23.5 mol of O2 .

At STP ( Standard Temperature and potential ) 1 mole of gas has 22.4 L of volume .The follow can be expressed as :


Mole = (given volume in L)/(22.4 L ) * 1 mol

Given volume of O2 gas = 526 L

Plugging value in the formula :


Mole = (526 L)/(22.4 L) * 1 mol

Mole of O2 gas at STP = 23.5 mol

User Crwils
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