Answer/Step-by-step explanation:
Apply trigonometric ratio to solve for x in all problems given.
1. Reference angle = 29°
Adjacent = x
Hypotenuse = 13 m
Thus:
![cos(29) = (x)/(13)](https://img.qammunity.org/2022/formulas/mathematics/high-school/m7qe62seyf2gf8vxy9ird5qhbzefm2o9o4.png)
Multiply both sides by 13
![13*cos(29) = x](https://img.qammunity.org/2022/formulas/mathematics/high-school/jqrhy9n4obkauqt6mon0nhslt7ww1j65n4.png)
11.4 = x (nearest tenth)
x = 11.4 m
2. Reference angle = 63°
Opp = 18 cm
Hypotenuse = x
Thus:
![sin(63) = (18)/(x)](https://img.qammunity.org/2022/formulas/mathematics/high-school/av1gx3z6b8iig4rc7fdk37j14d413u9cnv.png)
Multiply both sides by x
![x*sin(63) = 18](https://img.qammunity.org/2022/formulas/mathematics/high-school/z4hsu1ebzm0vba811u37bfx6sspra0zxgu.png)
Divide both sides by sin(63)
![x = (18)/(sin(63))](https://img.qammunity.org/2022/formulas/mathematics/high-school/w9bb67eky8cz7141mj58u7z7tcjfj8gwrs.png)
x = 20.2 cm (nearest tenth)
3. Reference angle = 71°
Opp = 14 ft
Adjacent = x
Thus:
![tan(71) = (14)/(x)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ssjjwwrtqmp7pben8ivilih2i0pjl3fawg.png)
Multiply both sides by x
![x*tan(71) = 14](https://img.qammunity.org/2022/formulas/mathematics/high-school/5bl99c5bgygm2b4spgh998gx2gzr73joaq.png)
Divide both sides by tan(71)
![x = (14)/(tan(71))](https://img.qammunity.org/2022/formulas/mathematics/high-school/obadxxaiecytjunkmsy7gj799w7wv8t4dx.png)
x = 4.8 ft (nearest tenth)