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Prove that (n+5)^2(n+3)^2 is a multiply of 4

User Lew
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1 Answer

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Solve for n:
(n + 3)^2 (n + 5)^2 = 0

Split into two equations:
(n + 3)^2 = 0 or (n + 5)^2 = 0

Take the square root of both sides:
n + 3 = 0 or (n + 5)^2 = 0

Subtract 3 from both sides:
n = -3 or (n + 5)^2 = 0

Take the square root of both sides:
n = -3 or n + 5 = 0
Subtract 5 from both sides:
Answer: n = -3 or n = -5 thus the Answer is wrong, neither -3 or -5 are a multiple of 4
User Jack Murphy
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