Question

A sample of argon initially has a volume of 5.0 L and the pressure is 2 atm. If the final temperature is 30° C, the final volume is 6 L, and the final pressure is 8atm, what was the initial temperature of the argon? Please give answer WITHOUT the unit of KELVIN and round to the tenth position (two places to the right of the decimal). Example: 25.14 not 25.4K

Answer 1

According to this formula:
(PiVi)/Ti = (PfVf)/Tf
when : Pi = intial pressure / Vi = intial volume / Ti = intial temperture
and: pf = final pressure / Vf = final volume / Tf = final temperture

Convert T from C° to Kelvin :
Tf = 30 + 273 = 303 K
by substitution in the previous formula :
(2 x 5 ) / Ti = (8 x 6) / 303
Ti = (303 x 10 ) / 48 = 63.125 K
Ti = 63.125 - 273 = - 209.88 C°