Question

If the digits of a three-digit number are reversed in order, then the sum of the new resulting number and the original number comes out to be 665. The difference of the two numbers is 297. The tens’ digit place is two times the hundreds’ place digit. What is the number?

Answer 1

First we have to setup system of equations for the given case.
Let x is the original number and y is the reverse three digit number.
Then,
x+y=665 Equation 1
x-y=297 Equation 2
Add both equations to get.
2x=962
Divide both sides by 2.
x=481
This is the original number. And reverse number is : 481+y=962
y=184

Here Hundredth digit is 4, and tenth digit is 8 which is 2 times of the hundredth digit.

Answer: Number is 481