Question

If there is a loss of 5.63 x 10-7kg of mass in a nuclear reaction, how many Joules of energy would be released? Recall that c = 3x108 m/s

3.92 x 104
3.92 x 1010
5.07 x 107
5.07 x 1010
6.26 x 10-24

Answer 1

`5.07* 10^(10)` Joules of energy would be released.

Step-by-step explanation:

Loss of mass in nuclear reaction= m =
`5.63* 10{^-7}kg`

Speed of light =
`c= 3* 10^(8) m/s`

Energy released = E

According to Einstein equation:

`E=mc^2`

`E=5.63* 10{^-7}kg* 3* 10^(8) m/s=5.07* 10^(10)J`

`5.07* 10^(10)` Joules of energy would be released.

Answer 2

E(energy) is released is calculated as
E=MC^2
E= energy in joules\
M=mass in Kg
C=is the speed of light

energy is therefore calculated as
((5.63 x 10^-7) {(3 x 10^8)^2)}=5.067 x 10 ^10 j( answer D)