Question

Tommy was walking at a rate of 4 miles per hour at noon and at 12:30 pm he was walking at a brisk rate of 6 miles per hour.Two hours later tommy was walking at a leisurely rate of 2 miles per hour. What was Tommy’s acceleration between noon and 12:30 pm?

Answer 1

Tommy had more acceleration between 12:30 and 2:30 pm

Answer 2

Tommy’s acceleration between noon and 12:30 pm is 4 miles/hr².

Step-by-step explanation:

Given that,

Initial velocity = 4 miles/hr

Final velocity = 6 miles/hr

Time t = 30 minutes

Acceleration :

Acceleration is the rate of change of the velocity of the particle.

We need to calculate the Tommy’s acceleration between noon and 12:30 pm

Using equation of motion

`v = u+at`

`a=(v-u)/(t)`

Where, v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the formula

`a=(2(6-4))/(1)`

`a=4\ miles/hr^2`

Hence, Tommy’s acceleration between noon and 12:30 pm is 4 miles/hr².