Question

A box rests on top of a flat bed truck. the box has a mass of m = 18 kg. the coefficient of static friction between the box and truck is μs = 0.86 and the coefficient of kinetic friction between the box and truck is μk = 0.69. 1) the truck accelerates from rest to vf = 16 m/s in t = 16 s (which is slow enough that the box will not slide). what is the acceleration of the box?

Answer 1

For this case, the first thing you should do is write the kinematic motion equation of the block.
We have then:
vf = vo + a * t
Where,
vf: Final speed.
vo: Initial speed.
a: acceleration.
t: time.
Substituting the values:
(16) = (0) + a * (16)
Clearing the acceleration:
a = 16/16 = 1m / s ^ 2
Note: the other data for this case are not used in this problem.
answer:
The acceleration of the box is 1m / s ^ 2