Question

A 0.1 kg bouncy ball moves toward a brick wall with a speed of 11 m/s. After colliding with the wall, the ball travels at a speed of 8.8 m/s in the OPPOSITE DIRECTION. What is the magnitude of the impulse experience by the ball?

Answer 1

Impulse is change in momentum. The initial momentum was
0.1kg*11m/s=1.1kg m/s.
The second momentum is 0.1*(-8.8m/s)=-0.88 (since it's moving backward now)
The difference is P1-P2 = 1.1-(-0.88)=1.98kg m/s