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A rectangle has a width of x centimeters and a perimeter of 8x centimeters a square has sides of length 1/4 that of the length of the rectangle.

A. Find the length of the rectangle
B. Find the perimeter of the square
C. Find how many cm greater the rectangle's perimeter if x=4
D. Find how many square cm greater the rectangle's area is than the square's area if x=4

2 Answers

1 vote

Answer:

4a) The length of the rectangle is 3x centimeters

4b) The squares perimeter is 3x centimeters

4c) 20 centimeters

4d) 39

User Edvinas
by
8.1k points
3 votes

Answer:

Part A) The length of rectangle is
3x\ cm

Part B) The perimeter of the square is
3x\ cm

Part C)
20\ cm

Part D)
39\ cm^(2)

Explanation:

Part A) Find the length of the rectangle

we know that

The perimeter of rectangle is equal to


P=2(L+W)

we have


P=8x\ cm


W=x\ cm

substitute and solve for L


8x=2(L+x)


4x=(L+x)


L=4x-x=3x\ cm

Part B) Find the perimeter of the square

we know that

The perimeter of a square is


P=4b

we have that


b=(1/4)L

substitute the value of L


b=(1/4)3x=(3/4)x\ cm

Find the perimeter of the square


P=4(3/4)x=3x\ cm

Part C) Find how many cm greater the rectangle's perimeter than the square's perimeter if x=4

Find the value of rectangle's perimeter


P=8x\ cm ------>
P=8(4)=32\ cm

Find the value of square's perimeter


P=3x\ cm ------>
P=3(4)=12\ cm

Find the difference


32\ cm-12\ cm=20\ cm

Part D) Find how many square cm greater the rectangle's area is than the square's area if x=4

Find the value of rectangle's area


A=(3x)(x)=3x^(2)\ cm^(2) ------>
A=3(4^(2))=48\ cm^(2)

Find the value of square's area


A=((3/4)x)^(2)\ cm^(2) ------>
A=((3/4)(4))^(2)=9\ cm^(2)

Find the difference


48\ cm^(2)-9\ cm^(2)=39\ cm^(2)

User Chnoch
by
7.4k points

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