Answer:
Vertical asymptotes x = 2, 5
Horizontal asymptotes y = 3
No oblique asymtotes.
Explanation:
The given function is f(x) = (3x²-2x-1)/(x²+3x-10)
We have to write the equations of the asymptotes of the graph of the function given.
Now we will factorize the denominator
Denominator is (x² + 3x -10) = x² + 5x - 2x -10 = x(x-5)-2(x-5) = (x-2)(x-5)
So the function is f(x) = (3x² -2x -1)/(x-2)(x-5)
So the vertical asymptotes are x = 2, 5
Horizontal asymptote is y = 3 ( Quotient of the function when we divide numerator by the denominator of the function)
No Oblique asymptotes.