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What are the equations of the asymptotes of the graph of the function f(x)=3x^2-2x-1/x^2+3x-10

User Amgaera
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2 Answers

3 votes

Answer:

the answer is x = –5, x = 2 and y = 3

Explanation:


User Huy Than
by
8.3k points
3 votes

Answer:

Vertical asymptotes x = 2, 5

Horizontal asymptotes y = 3

No oblique asymtotes.

Explanation:

The given function is f(x) = (3x²-2x-1)/(x²+3x-10)

We have to write the equations of the asymptotes of the graph of the function given.

Now we will factorize the denominator

Denominator is (x² + 3x -10) = x² + 5x - 2x -10 = x(x-5)-2(x-5) = (x-2)(x-5)

So the function is f(x) = (3x² -2x -1)/(x-2)(x-5)

So the vertical asymptotes are x = 2, 5

Horizontal asymptote is y = 3 ( Quotient of the function when we divide numerator by the denominator of the function)

No Oblique asymptotes.

User AndreG
by
8.0k points

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