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Given that P = (2, 9) and Q = (4, 14), find the component form and magnitude of PQ.

a. <2, 5>, square root of 29
b. <-2, -5>, 29
c. <2, 5>, 29
d. <-2, -5> square root of 29

1 Answer

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The first thing you should know is that to find the vector, PQ we must subtract both points:
PQ = Q-P = (4, 14) - (2, 9) = (2, 5)
The module of this vector is given by
lPQl = root ((2) ^ 2 + (5) ^ 2)
lPQl = root (29)
answer
PQ = (2, 5)
lPQl = root (29)
a. <2, 5>, square root of 29
User Mkurz
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