Question

1. A compound is made up of 11 percent oxygen and 89 percent gold. What would be this compound's

empirical formula?

Answer 1

Empirical formula is Au₂O₃

Step-by-step explanation:

Given data:

Percentage of oxygen = 11%

Percentage of gold = 89%

Empirical formula = ?

Solution:

Solution:

Number of gram atoms of O = 11 / 16 = 0.69

Number of gram atoms of Au = 89 / 197 = 0.45

Atomic ratio:

Au : O

0.45/0.45 : 0.69 /0.45

1 : 1.5

Au : O = 1 : 1.5

Au : O = 2( 1 : 1.5)

Empirical formula is Au₂O₃.