Question

2. A compound has the following composition. 49 percent oxygen, 21 percent nitrogen, 24 percent sulfur,

and 6 percent hydrogen. What is this compound's empirical formula?
I

Answer 1

Empirical formula : N₂H₈O₄S

Step-by-step explanation:

Percentage of hydrogen = 6%

Percentage of nitrogen = 21%

Percentage of oxygen = 49 %

Percentage of sulfur = 24 %

Empirical formula = ?

Solution:

Number of gram atoms of H = 6 / 1.01 = 5.9

Number of gram atoms of O = 49 / 16 = 3.1

Number of gram atoms of N = 21 / 14 = 1.5

Number of gram atoms of S = 24 / 32 = 0.75

Atomic ratio:

N : H : O : S

1.5/0.75 : 5.9/0.75 : 3.1/0.75 : 0.75/0.75

2 : 8 : 4 : 1

N:H:O:S = 2 : 8 : 4: 1

Empirical formula : N₂H₈O₄S