166k views
4 votes
Multiply the following polynomials and enter the MISSING LINEAR Term :

−3y(5y3 + 11y2 − y + 8) =−15y4 −33y3 + 3y2 − _____?_____

2 Answers

3 votes
- 15y4 - 33y3 + y2 + 8 = - 33y3 + 3y2
- 15y4 - 2y3 + 8
User Fallup
by
8.9k points
2 votes

We are given


-3y(5y^3+11y^2-y+8)=-15y^4-33y^3+3y^2-........?........

Firstly, we will simplify left side

and then we can compare it with right side

Left side:


-3y(5y^3+11y^2-y+8)

We can distribute -3y


=-3y*5y^3+-3y*11y^2--3y*y+-3y*8

now, we can simplify it


=-15y^4-33y^3+3y^2-24y

now, we can compare it with right side

we can see that only last term is missing

so, there should be -24y in last term

so, we get


-3y(5y^3+11y^2-y+8)=-15y^4-33y^3+3y^2-24y.................Answer

User Redlab
by
8.4k points